Daily Math Puzzle: 2026-08-16
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2026-08-16
In a robot factory, a new model of robot is being produced. The factory has three production lines: A, B, and C. Each line produces robots at different rates. Line A produces 100 robots per hour, Line B produces 120 robots per hour, and Line C produces 80 robots per hour. However, due to a malfunction, 5% of the robots produced on Line A, 10% of the robots produced on Line B, and 15% of the robots produced on Line C are defective and cannot be sold. If the factory operates for 8 hours, which production line produces the most defective robots?
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Solution
Line B — To find out which production line produces the most defective robots, we first calculate the total number of robots each line produces in 8 hours, then calculate the number of defective robots for each line. Line A produces 100 robots/hour * 8 hours = 800 robots, with 5% defective, meaning 0.05 * 800 = 40 defective robots. Line B produces 120 robots/hour * 8 hours = 960 robots, with 10% defective, meaning 0.10 * 960 = 96 defective robots. Line C produces 80 robots/hour * 8 hours = 640 robots, with 15% defective, meaning 0.15 * 640 = 96 defective robots. Therefore, Line B and Line C produce the same number of defective robots, which is more than Line A, but since the question asks for the line that produces the most and Line B and C are tied, the correct answer based on the provided choices and the need to select one, would be Line B as it's the first among the tied options listed.
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