Daily Math Puzzle: 2026-05-23
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2026-05-23
In a robot factory, three assembly lines work for 4 hours each day. - Line A builds 5 robots every hour. - Line B builds 3 robots every hour. - Line C builds 4 robots every hour. At the end of each hour, the factory moves 2 robots from Line A’s stock to Line B, and 1 robot from Line B’s stock to Line C. (Robots are only moved; none are created or destroyed by the transfers.) How many robots are in the factory in total at the end of the 4‑hour shift?
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Solution
48 robots — First find how many robots are *produced* in total, ignoring the moves, because moving robots does not change the overall count.
- Line A: 5 robots/hour × 4 hours = 20 robots
- Line B: 3 robots/hour × 4 hours = 12 robots
- Line C: 4 robots/hour × 4 hours = 16 robots
Total produced = 20 + 12 + 16 = 48 robots.
The hourly transfers (2 from A to B and 1 from B to C) merely relocate robots between lines; they do not add or remove any robots. Therefore the factory still has 48 robots at the end of the shift. The trick is not to double‑count the robots that are moved.
Hence the correct answer is the second choice, "48 robots".
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