The value of the integral ∫(x^2 + 1) / (x^2 - 4) dx is
Correct: B
To evaluate the integral, we can use partial fractions. Let (x^2 + 1)/(x^2 - 4) = A/(x - 2) + B/(x + 2). Solving for A and B gives A = B = 1/4. So the integral becomes ∫(1/4)(1/(x - 2) + 1/(x + 2)) dx = (1/4)log|x - 2| + (1/4)log|x + 2| + c