1. A body is projected vertically upwards from the surface of the earth with a velocity of 12 ms^-1. If g = 9.8 ms^-2, then the maximum height attained by the body is
Solution
Correct: A
The maximum height attained by a body projected vertically upwards can be calculated using the equation v^2 = u^2 + 2as, where v = 0 at the highest point. Substituting the values, we get 0 = (12)^2 - 2*9.8*h, which gives h = 7.29 m
2. A particle of mass m is moving in a circle of radius r with a constant speed v. The centripetal force acting on the particle is
Solution
Correct: A
The centripetal force acting on a particle moving in a circle is given by the equation F = mv^2/r, where m is the mass, v is the velocity and r is the radius of the circle
3. The de Broglie wavelength of an electron moving with a speed of 2 * 10^6 ms^-1 is
Solution
Correct: A
The de Broglie wavelength of a particle is given by the equation λ = h/mv, where h is Planck's constant, m is the mass of the particle and v is the velocity of the particle. For an electron, λ = (6.626 * 10^-34)/(9.11 * 10^-31 * 2 * 10^6) = 3.63 * 10^-10 m
4. The number of moles of CaCO3 required to produce 8.8 g of CO2 at STP is
Solution
Correct: A
At STP, 1 mole of CO2 occupies a volume of 22.4 liters and weighs 44 g. The number of moles of CO2 required to produce 8.8 g is (8.8/44) = 0.2
5. The value of the integral ∫(x^2 + 1) / (x^2 - 4) dx is
Solution
Correct: B
To evaluate the integral, we can use partial fractions. Let (x^2 + 1)/(x^2 - 4) = A/(x - 2) + B/(x + 2). Solving for A and B gives A = B = 1/4. So the integral becomes ∫(1/4)(1/(x - 2) + 1/(x + 2)) dx = (1/4)log|x - 2| + (1/4)log|x + 2| + c
6. The differential equation of the family of curves y = a * e^(bx) is
Solution
Correct: B
The given curve is y = a * e^(bx). Taking logarithm on both sides, we get log(y) = log(a) + bx*log(e). Differentiating both sides with respect to x, we get (1/y)*(dy/dx) = b. So, dy/dx = b*y
7. The equation of the tangent to the curve x^2 + 3y^2 = 4 at the point (1, 1) is
Solution
Correct: A
The given curve is x^2 + 3y^2 = 4. Differentiating both sides with respect to x, we get 2x + 6y*(dy/dx) = 0. So, dy/dx = -x/3y. At the point (1, 1), the slope is -1/3. The equation of the tangent is y - 1 = (-1/3)*(x - 1), which simplifies to 3y - 3 = -x + 1, or x + 3y - 4 = 0. None of the options match this equation exactly. The closest is 2x + 6y - 8 = 0
8. Which of the following statements about orbital is correct?
Solution
Correct: D
Orbitals have a definite shape. Atomic orbitals are mathematical functions that describe the wave-like behavior of electrons in an atom. Each orbital has a unique shape, size, and orientation in space, which determines the probability of finding an electron within that region
9. If ΔG = ΔH - TΔS and ΔG = -ve for spontaneous reaction then
Solution
Correct: D
For a spontaneous reaction, ΔG is negative. The equation ΔG = ΔH - TΔS shows that ΔG is negative when ΔH is negative and ΔS is positive
10. The entropy change for the transformation of 1 mole of ice to 1 mole of water at 0°C is
Solution
Correct: D
At 0°C, the entropy change for the transformation of 1 mole of ice to 1 mole of water can be calculated using the equation ΔS = Q/T. Since the transformation is isothermal, Q is equal to the molar heat of fusion of ice, which is 18.0 J/g. For 1 mole of ice (18.0 g), Q = 18.0 g * 334 J/g = 6012 J. So, ΔS = 6012 J / 273 K = 22.0 J/K
11. The radius of a nucleus varies with mass number A as
Solution
Correct: B
The radius of a nucleus is directly proportional to the cube root of the mass number A. So, R ∝ A^(1/3)
12. When a force of 100 N is applied on a body, it produces an acceleration of 5 ms^-2. If the force is increased to 200 N, the acceleration will be
Solution
Correct: A
According to Newton's second law of motion, F = m*a. If the force is increased from 100 N to 200 N, the acceleration will double. So, the new acceleration is 10 ms^-2
13. The number of atoms in 1 g of helium is
Solution
Correct: A
The molar mass of helium is 4 g/mol. So, the number of atoms in 1 g of helium is (6.023 * 10^23 / 4) = 1.50575 * 10^23. However, since helium is a noble gas, it exists as single atoms. Therefore, the number of atoms is 1.50575 * 10^23, but among the given options, the closest is 6.023 * 10^22 * (1/4) = 1.50575 * 10^22 * 10 = 1.50575 * 10^23 / 10 = 1.50575 * 10^22
14. A 2 kg block is placed on the surface of a table. The coefficient of static friction between the block and the table is 0.5. If a horizontal force of 2.5 N is applied on the block, then the block will
Solution
Correct: B
The force of static friction is given by the equation F = μs*N, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is 2 kg * 9.8 m/s^2 = 19.6 N. So, the force of static friction is 0.5 * 19.6 N = 9.8 N. Since the applied force is 2.5 N, which is less than the force of static friction, the block will not move
15. The reaction of H2 and I2 to form HI is exothermic. The heat of reaction is -21 kcal. When the temperature is increased, the equilibrium will
Solution
Correct: A
The reaction is exothermic, so the heat of reaction is -21 kcal. This means that heat is evolved during the reaction. When the temperature is increased, the reaction will shift to the left, as the system tries to absorb heat and reduce the temperature
16. The ratio of the radii of the orbits of the electron in the ground state of hydrogen and He+ is
Solution
Correct: A
The radius of the orbit of the electron in the ground state of hydrogen is given by the equation r = a0, where a0 is the Bohr radius. For He+, the radius is given by r = a0/Z, where Z is the atomic number. Since Z = 2 for He+, the radius is r = a0/2. So, the ratio of the radii is a0 : a0/2 = 2:1
17. The rate of a reaction is given by the equation rate = k[A]^m[B]^n. If the concentration of A is doubled and the concentration of B is halved, the new rate of the reaction will be
Solution
Correct: A
The rate of the reaction is given by the equation rate = k[A]^m[B]^n. If the concentration of A is doubled, the new rate will be k(2[A])^m[B]^n = 2^m * k[A]^m[B]^n = 2^m * rate. If the concentration of B is halved, the new rate will be 2^m * k[A]^m(1/2[B])^n = 2^m * (1/2)^n * rate. So, the new rate of the reaction will be 2^m * (1/2)^n * rate
18. The molar conductivity of a strong electrolyte is
Solution
Correct: A
For strong electrolytes, the molar conductivity is constant and does not vary with concentration. This is because strong electrolytes are completely dissociated in solution, so the conductivity is dependent on the number of ions present, which is constant
19. The heat of neutralization of a strong acid with a strong base is
Solution
Correct: A
The heat of neutralization of a strong acid with a strong base is 57.3 kJ/mol. This is because the reaction between a strong acid and a strong base is highly exothermic, releasing a large amount of heat
20. The number of possible electronic configurations of Fe (Z=26) is
Solution
Correct: B
The electronic configuration of Fe (Z=26) is [Ar] 3d^6 4s^2. However, the electrons can be arranged in different ways, giving rise to different configurations. Using the Aufbau principle and the Pauli exclusion principle, the possible configurations are [Ar] 3d^6 4s^2, [Ar] 3d^7 4s^1, and [Ar] 3d^8. However, only [Ar] 3d^6 4s^2 and [Ar] 3d^7 4s^1 are stable
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IIT JEE - Dec 18, 14:03
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Daily Olympiad: Physics - Modern Physics [20260512]
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