Daily Math Puzzle: 2026-10-13

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2026-10-13

Detective Eleanor Vance is investigating a baffling case at the 'Chronos Bank'. A priceless artifact was stolen from a vault described as a perfect square room. The vault's high-tech security system reported no forced entry, only a 'structural re-alignment' event. Upon inspection, the vault walls appeared to have been subtly moved, transforming the square room into a rectangular room with a length of 12 meters and a width of 8 meters. The thief left a cryptic note: 'I didn't break in; I just made more room... or less!' Detective Vance needs to determine the precise change in the floor area of the vault to understand the thief's method and identify the unique tool used for the 're-alignment'. Assuming the original square vault had the same perimeter as the altered rectangular vault, what is the exact difference in the vault's floor area before and after the re-alignment?

2 square meters4 square meters6 square meters8 square meters

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Solution

4 square meters — First, calculate the perimeter of the altered rectangular vault: Perimeter = 2 * (Length + Width) = 2 * (12m + 8m) = 2 * 20m = 40 meters. The puzzle states that the original square vault had the *same perimeter* as the altered rectangular vault. So, the square vault's perimeter was also 40 meters. For a square, Perimeter = 4 * side. Therefore, 40m = 4 * side, which means the side length of the original square vault was 10 meters. The area of the original square vault was side * side = 10m * 10m = 100 square meters. The area of the altered rectangular vault is Length * Width = 12m * 8m = 96 square meters. The difference in floor area before and after the re-alignment is 100 sq m - 96 sq m = 4 square meters.

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