Daily Math Puzzle: 2026-09-28
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2026-09-28
In the mystical realm of Eldoria, an ancient wizard offers you a chance to claim a legendary artifact. He presents a magical 'Orb of Fate' with three distinct faces: 'Success', 'Failure', and 'Neutral'. Each face has an equal probability of appearing when the orb is activated. You must activate the orb up to two times following these rules: 1. You activate the orb once. 2. If the first activation shows 'Success', you immediately win the artifact. 3. If the first activation shows 'Failure', you immediately lose the challenge and get nothing. 4. If the first activation shows 'Neutral', you must activate the orb a second time. 5. If the second activation shows 'Success', you win the artifact. 6. If the second activation shows 'Failure', you lose the challenge. 7. If the second activation shows 'Neutral', nothing happens; you neither win nor lose, ending the challenge inconclusively. What is the probability that you win the legendary artifact?
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Solution
4/9 — To win the legendary artifact, there are two distinct sequences of events that lead to a win:
**Path 1: Win on the first activation.**
This occurs if the first activation of the Orb of Fate shows 'Success'.
The probability of 'Success' on any given activation is 1/3 (since there are three faces with equal probability: Success, Failure, Neutral).
So, P(Win via Path 1) = 1/3.
**Path 2: Win on the second activation.**
This path can only occur if the first activation shows 'Neutral', AND then the second activation shows 'Success'.
* The probability of the first activation being 'Neutral' is 1/3.
* If the first activation is 'Neutral', you proceed to activate the orb a second time. The outcome of this second activation is independent of the first.
* The probability of the second activation being 'Success' is also 1/3.
To find the probability of both these independent events happening in sequence, we multiply their probabilities:
P(Win via Path 2) = P(First is Neutral) × P(Second is Success) = (1/3) × (1/3) = 1/9.
Since Path 1 and Path 2 are mutually exclusive (they cannot both happen for the same challenge), the total probability of winning is the sum of their individual probabilities:
Total P(Win) = P(Win via Path 1) + P(Win via Path 2)
Total P(Win) = 1/3 + 1/9
To add these fractions, we find a common denominator, which is 9:
Total P(Win) = 3/9 + 1/9 = 4/9.
Therefore, the probability of winning the legendary artifact is 4/9.
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