Daily Math Puzzle: 2026-05-11

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2026-05-11

The High Priestess of the forgotten civilization of Xylos was tasked with organizing ancient, fragile scrolls into special ceremonial boxes. She noted that if she placed 8 scrolls into each box, there were 5 scrolls left over, unable to fit into any box. However, if she attempted to place 9 scrolls into each box, she found she would need 3 additional scrolls to fill all the boxes completely. How many ceremonial boxes did the High Priestess possess?

581217

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Solution

8 — Let 'B' represent the number of ceremonial boxes and 'S' represent the total number of scrolls. From the first statement: 'if she placed 8 scrolls into each box, there were 5 scrolls left over'. This can be expressed as an equation: S = 8B + 5 (Equation 1) From the second statement: 'if she attempted to place 9 scrolls into each box, she found she would need 3 additional scrolls'. This means that to fill all 'B' boxes with 9 scrolls each, she would need 3 more scrolls than she currently has. So, the total number of scrolls required would be S + 3. S + 3 = 9B (Equation 2a) We can rearrange Equation 2a to solve for S: S = 9B - 3 (Equation 2b) Now we have two expressions for S (the total number of scrolls). We can set them equal to each other to solve for B (the number of boxes): 8B + 5 = 9B - 3 To solve for B, we need to gather all the 'B' terms on one side of the equation and the constant terms on the other side. Subtract 8B from both sides: 5 = 9B - 8B - 3 5 = B - 3 Add 3 to both sides: 5 + 3 = B 8 = B Therefore, the High Priestess possessed 8 ceremonial boxes.

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