A Puzzle A Day: 2026-04-16

In the ancient city of Ozymandias, three types of exotic fruits were highly prized: the Solar Plum (S), the Lunar Berry (L), and the Stellar Fig (F). Merchants used a peculiar weighing system based on these fruits: 1. Two Solar Plums and one Lunar Berry together weigh 25 units. 2. One Lunar Berry and two Stellar Figs together weigh 29 units. 3. Two Stellar Figs and one Solar Plum together weigh 22 units. What is the average weight of a single Solar Plum, a single Lunar Berry, and a single Stellar Fig?
Correct: 9 units
Let the weight of a Solar Plum be S, a Lunar Berry be L, and a Stellar Fig be F. We are given the following system of equations: 1. 2S + L = 25 2. L + 2F = 29 3. 2F + S = 22 We need to find the average weight, which is (S + L + F) / 3. One way to solve this is to solve for S, L, and F individually. Let's try adding equations (1) and (3), and then subtracting equation (2): (2S + L) + (2F + S) - (L + 2F) = 25 + 22 - 29 3S + L + 2F - L - 2F = 47 - 29 3S = 18 S = 6 Now that we have S = 6, we can substitute it back into equations (1) and (3) to find L and F: From (1): 2(6) + L = 25 12 + L = 25 L = 13 From (3): 2F + 6 = 22 2F = 16 F = 8 So, the weights are: Solar Plum (S) = 6 units, Lunar Berry (L) = 13 units, and Stellar Fig (F) = 8 units. Let's verify these values with equation (2): L + 2F = 13 + 2(8) = 13 + 16 = 29. This matches the given information. Now, calculate the total weight of one of each fruit: S + L + F = 6 + 13 + 8 = 27 units. The question asks for the *average* weight, which is the total weight divided by the number of fruits (3): Average Weight = (S + L + F) / 3 = 27 / 3 = 9 units. The correct answer is 9 units.
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