Daily Math Puzzle: 2026-03-12

25 — Let the two-digit number be represented as 10A + B, where A is the tens digit and B is the units digit. When the digits are swapped, the new number is 10B + A. According to the first condition, the new number is 27 greater than the original number: 10B + A = (10A + B) + 27 Subtract (10A + B) from both sides: (10B + A) - (10A + B) = 27 9B - 9A = 27 Divide by 9: B - A = 3 This means the units digit (B) must be 3 greater than the tens digit (A). Let's list all two-digit numbers that satisfy this condition: - If A=1, B=4, the number is 14 (swapped: 41; 41-14=27) - If A=2, B=5, the number is 25 (swapped: 52; 52-25=27) - If A=3, B=6, the number is 36 (swapped: 63; 63-36=27) - If A=4, B=7, the number is 47 (swapped: 74; 74-47=27) - If A=5, B=8, the number is 58 (swapped: 85; 85-58=27) - If A=6, B=9, the number is 69 (swapped: 96; 96-69=27) The second condition states that the number is a multiple of 5. A number is a multiple of 5 if its units digit (B) is either 0 or 5. Looking at our list of possible numbers from the first condition (14, 25, 36, 47, 58, 69): - Only 25 has a units digit of 5. Therefore, the only number that satisfies both conditions is 25.