Daily Olympiad: Physics - Magnetic Effects Current [20260511]

Challenge yourself with today's JEE Main practice! This test covers 'Magnetic Effects Current' for Physics (JEE Main - 12). Level: Hard | Duration: 45 mins.

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1. A very long straight conductor carries a current I. A point P lies at a perpendicular distance d from the conductor. What is the magnitude of the magnetic field at point P?

Solution
Correct: A
The magnetic field around a long straight conductor is given by Ampere’s Law: B = μ₀I/(2πd). This is derived by considering a circular Amperian loop around the wire. Incorrect options often result from missing constants or misapplying the formula.

2. Two long parallel conductors carry currents I₁ and I₂ in opposite directions. The forces on them are:

Solution
Correct: B
Parallel currents in opposite directions produce repulsive forces. This follows from the right-hand rule for each wire's field and the force on the other wire. A common mistake is confusing directions based on the right-hand or left-hand rule.

3. A circular loop of radius R carries current I. At the center, the magnetic field due to an infinitesimal segment of the loop is perpendicular to the plane of the loop. What is the direction of the net magnetic field?

Solution
Correct: A
Using the right-hand rule, each segment of the loop contributes a magnetic field perpendicular to the plane. The vector sum is along the axis (perpendicular), as only the axial components add constructively. Radial components cancel out due to symmetry.

4. A rectangular coil with 100 turns, each of area 0.01 m², is placed in a uniform magnetic field of 0.5 T. If a current of 2 A flows and the coil rotates such that its normal makes a 30° angle with the field, what is the maximum torque?

Solution
Correct: C
Torque τ = N I A B sinθ = 100 * 2 * 0.01 * 0.5 * sin(30°) = 0.5 N·m. The maximum torque occurs at θ = 90°, but since the question specifies 30°, calculations must apply the sine factor correctly. Misreading θ or missing N leads to other options.

5. A charge particle of mass m and charge q moves in a magnetic field with velocity v perpendicular to the field. Which of these does NOT affect the particle’s orbital radius?

Solution
Correct: D
The orbital radius r = mv/(qB). Velocity, charge, and magnetic field directly affect r, but mass does not appear in the formula. This is a common misconception; students often think mass affects radius during motion calculations.

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