A spring of force constant 100 N/m is stretched by 2 m. What is the potential energy stored in the spring?
Correct: B
Potential energy (U) stored in a spring is given by U = 1/2 kx^2, where k is the force constant and x is the displacement. Given, k = 100 N/m, x = 2 m. Substituting these values gives U = 1/2 × 100 × (2)^2 = 200 J.