A block of mass 2 kg is placed on a smooth horizontal surface. A force of 5 N acts on the block for 2 s. What will be the change in momentum of the block?
Correct: B
Momentum (p) is given by p = mv, where m is the mass and v is the velocity. The change in momentum (Δp) is given by Δp = F × Δt, where F is the force applied and Δt is the time for which the force is applied. Given, F = 5 N, Δt = 2 s. So, Δp = 5 × 2 = 10 kg m/s.