A cube of side 2 m is immersed in water. If the density of water is 1000 kg/m^3, what will be the buoyant force on the cube?
Correct: B
The buoyant force (F) is given by F = ρVg, where ρ is the density of the fluid, V is the volume of the immersed object, and g is the acceleration due to gravity. Given, ρ = 1000 kg/m^3, V = (2)^3 = 8 m^3. Assuming g = 10 m/s^2, F = 1000 × 8 × 10 = 80000 N = 8000 × 10 N.