What is the time period of a simple pendulum of length 1 m at a place where the acceleration due to gravity is 9.8 m/s^2?
Correct: B
Time period (T) of a simple pendulum is given by T = 2π √(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. Given, l = 1 m, g = 9.8 m/s^2. Substituting these values in the equation gives T = 2π √(1/9.8) = 2 s.