For the equilibrium reaction 2NO2(g) ⇌ N2O4(g), the partial pressures of NO2 and N2O4 at equilibrium are 0.4 atm and 0.2 atm, respectively. What is the value of Kp?
Correct: @
Kp is calculated as [N2O4]/[NO2]^2 = (0.2)/(0.4^2) = 0.2/0.16 = 1.25. However, since the correct answer is not listed, this indicates a need to recheck calculations or problem setup. Correct Kp = 1.25.