Ramesh walked 20 meters towards the North, then turned right and walked 30 meters. Then he turned right and walked 35 meters. Then he turned left and walked 15 meters. Then he again turned left and walked 15 meters. What is the shortest distance between his initial and final positions?
Correct: B
Let Ramesh's initial position be the origin (0,0).
1. Walks 20 meters North: Position becomes (0, 20).
2. Turns right (East) and walks 30 meters: Position becomes (0+30, 20) = (30, 20).
3. Turns right (South) and walks 35 meters: Position becomes (30, 20-35) = (30, -15).
4. Turns left (East) and walks 15 meters: Position becomes (30+15, -15) = (45, -15).
5. Turns left (North) and walks 15 meters: Position becomes (45, -15+15) = (45, 0).
The final position is (45, 0) relative to his initial position (0,0).
The horizontal displacement is 45 meters East, and the vertical displacement is 0 meters.
Therefore, the shortest distance between his initial and final positions is 45 meters.