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Problem 1 - Entrance Test

A person walks 10m North, turns right and walks 5m, then turns left and walks 10m, and finally turns right and walks 10m. What is the final distance and direction from the starting point?

Correct: B

Let the starting point be the origin (0,0). 1. Walks 10m North: Position becomes (0, 10). 2. Turns right (East) and walks 5m: Position becomes (0+5, 10) = (5, 10). 3. Turns left (North) and walks 10m: Position becomes (5, 10+10) = (5, 20). 4. Turns right (East) and walks 10m: Position becomes (5+10, 20) = (15, 20). The final position is (15, 20) relative to the starting point (0,0). The horizontal displacement is 15m East, and the vertical displacement is 20m North. The direction from the starting point is North-East. The shortest distance is calculated using the Pythagorean theorem: Distance = sqrt((15)^2 + (20)^2) = sqrt(225 + 400) = sqrt(625) = 25m. Therefore, the final position is 25m North-East from the starting point.