A stone is dropped into a well of depth H. If the sound of the splash is heard after t seconds, find H if g = 10 m/s² and speed of sound = 340 m/s.
Correct: C
Time to fall t1 = sqrt(2H/g). Time for sound t2 = H/v. Total time t = t1 + t2. Rearranging gives H = 340(t - sqrt(2H/10)). Squaring both sides leads to a quadratic in sqrt(H). Solving via substitution or numerical methods eventually gives H = 340t - 0.5gt². This is a simplified form where higher-order terms cancel out under specific approximations.