A car accelerates from rest at 2 m/s² for 5 seconds, then decelerates at 1 m/s² until it stops. What is the total distance covered?
Correct: C
First phase: v = a1*t1 = 10 m/s, distance s1 = 0.5*a1*t1² = 25 m. Second phase: time to stop t2 = v/a2 = 10 s. Distance s2 = v*t2 - 0.5*a2*t2² = 100 - 50 = 50 m. Total distance = 25 + 50 = 75 m. Wait, correction in calculation: s2 should be (10*10)/2 = 50 m. Total distance = 25 + 50 = 75 m, but none of the options match. Reviewing problem, t2 must be 10 seconds, so (10²)/(2*1) = 50. Total 25 + 50 = 75. However, no correct option suggests a possible miscalculation. Re-evaluate: t2 = 10 s, average velocity (10 + 0)/2 = 5 m/s, s2 = 50 m. Total 75 m. No matching option indicates a typo or oversight. Correct answer is 75 m, but options provided imply a different context.