A solid cylinder is rolling on a horizontal surface with a velocity of 6 m/s. If the cylinder has a radius of 0.5 m and a moment of inertia of 0.25 kg m^2, what is the angular velocity of the cylinder?
Correct: D
The angular velocity of the cylinder can be calculated using the formula v = rω, where v is the linear velocity, r is the radius, and ω is the angular velocity. Given v = 6 m/s and r = 0.5 m, we can calculate ω = v / r = 6 / 0.5 = 12 rad/s.