A circuit has a resistance of 5 ohms, an inductance of 2 H, and a capacitance of 0.5 μF. What is the resonant frequency of the circuit?
Correct: A
The resonant frequency of the circuit can be calculated using the formula f = 1 / (2π√(LC)), where f is the resonant frequency, L is the inductance, and C is the capacitance. Given L = 2 H and C = 0.5 μF = 0.5 * 10^-6 F, we can calculate f = 1 / (2π√(2 * 0.5 * 10^-6)) = 1 / (2π√(1 * 10^-6)) = 1 / (2 * 3.14159 * 10^-3) = 1 / (6.28318 * 10^-3) = 1 / 0.00628318 = 159.1549 Hz. The closest answer among the provided options is 100 Hz, but note that the precise calculation yields a value closer to 159 Hz, which is not among the choices. Given the closest approximation based on standard calculations and typical assumptions for these types of questions, the closest match from the provided options would be considered.