Find the value of the integral of x^2 from x = 0 to x = 2.
Correct: A
The integral of x^2 from x = 0 to x = 2 is ∫[0,2] x^2 dx. Using the power rule of integration, which states that ∫x^n dx = (x^(n+1))/(n+1) + C, we have ∫x^2 dx = (x^3)/3 + C. Evaluating this expression at the limits of integration gives [(2^3)/3] - [(0^3)/3] = 8/3 - 0/3 = 8/3.