← Back to Test

Problem 17 - Entrance Test

Evaluate ∫0^π sin^2 x dx.

Correct: A

Use identity sin^2 x = (1 - cos 2x)/2. Integral becomes 1/2 ∫0^π (1 - cos 2x) dx = 1/2 [x - sin 2x/2]_0^π = 1/2·π = π/2.