What is the value of the integral of (2x + 1) dx from x = 0 to x = 1?
Correct: A
To find the value of the integral of (2x + 1) dx from x = 0 to x = 1, we can integrate the expression term by term. The integral of 2x is x^2, and the integral of 1 is x. Therefore, the integral of (2x + 1) is x^2 + x + C. Evaluating this integral from x = 0 to x = 1, we get [(1^2 + 1)] - [(0^2 + 0)] = 2.