What is the equation of the curve that passes through the point (0, 1) and has a derivative of 2x at that point?
Correct: A
The derivative of the curve is given as 2x. We can find the equation of the curve by integrating the derivative. The integral of 2x is x^2 + C. Since the curve passes through the point (0, 1), we can plug in x = 0 and y = 1 to get 1 = 0^2 + C, so C = 1. Therefore, the equation of the curve is y = x^2 + 1.