What is the value of the integral of x^2 dx from x = 0 to x = 1?
Correct: B
To find the value of the integral of x^2 dx from x = 0 to x = 1, we can use the power rule of integration, which is ∫x^n dx = (x^(n+1))/(n+1) + C. Applying this rule with n = 2, we get ∫x^2 dx = (x^3)/3 + C. Evaluating this integral from x = 0 to x = 1, we get [(1^3)/3] - [(0^3)/3] = 1/3.