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Problem 8 - Olympiad

If ω is a complex cube root of unity (ω ≠ 1), then the value of the determinant | 1 1 1 |

Correct: A

Given ω is a primitive cube root of unity, so ω^3 = 1 and 1 + ω + ω^2 = 0. The determinant is: | 1 1 1 |