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Problem 5 - Olympiad

The value of the determinant | 1 1 1 |

Correct: B

The determinant evaluates to 0. Using the property that if two rows (or columns) are identical, the determinant is zero. Expanding along the first row: 1·(b·c - b·c) - 1·(a·c - a·c) + 1·(a·b - a·b) = 0. Alternatively, subtracting Row 2 from Row 1 and Row 3 from Row 1 gives two identical rows, making the determinant zero.