The potential energy of a spring is given by the equation U = 1/2 kx^2. If the spring constant is 100 N/m and the spring is stretched by 2 m, find the potential energy.
Correct: D
Using the given equation, U = 1/2 kx^2. Given k = 100 N/m, x = 2 m. So, U = 1/2 * 100 * (2)^2 = 200 J.