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Problem 3 - Entrance Test
A particle is moving in a circular path of radius 2 m with a velocity of 4 m/s. Find the centripetal acceleration of the particle.
A. A) 2 m/s^2
B. B) 4 m/s^2
C. C) 6 m/s^2
D. D) 8 m/s^2
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Correct: D
Using the formula for centripetal acceleration, a = v^2/r. Given v = 4 m/s, r = 2 m. So, a = (4)^2 / 2 = 8 m/s^2.