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Problem 20 - Entrance Test
A particle is moving in a circular path of radius 3 m with a velocity of 6 m/s. Find the centripetal force acting on the particle. (m = 2 kg)
A. A) 12 N
B. B) 24 N
C. C) 36 N
D. D) 48 N
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Correct: B
Using the formula for centripetal force, F = mv^2/r. Given m = 2 kg, v = 6 m/s, r = 3 m. So, F = 2 * (6)^2 / 3 = 24 N.