The reaction of CO2 and H2O to form H2CO3 is given by CO2 + H2O → H2CO3. If 10 g of CO2 reacts with 10 g of H2O, find the mass of H2CO3 formed.
Correct: B
Using the stoichiometry of the reaction, the molar masses of CO2, H2O, and H2CO3 are 44 g/mol, 18 g/mol, and 62 g/mol respectively. Given 10 g of CO2 and 10 g of H2O, we can calculate the number of moles of each. Moles of CO2 = 10/44 = 0.227 mol. Moles of H2O = 10/18 = 0.556 mol. From the reaction, 1 mole of CO2 reacts with 1 mole of H2O to form 1 mole of H2CO3. The limiting reagent is CO2. Hence, the moles of H2CO3 formed = 0.227 mol. Mass of H2CO3 formed = 0.227 * 62 = 14.074 g.