The reaction of Zn and CuSO4 is given by Zn + CuSO4 → ZnSO4 + Cu. If 50 g of Zn reacts with 100 g of CuSO4, find the mass of Cu formed.
Correct: D
Using the stoichiometry of the reaction, the molar masses of Zn, CuSO4, ZnSO4, and Cu are 65.38 g/mol, 159.6 g/mol, 161.44 g/mol, and 63.55 g/mol respectively. Given 50 g of Zn and 100 g of CuSO4, we can calculate the number of moles of each. Moles of Zn = 50/65.38 = 0.765 mol. Moles of CuSO4 = 100/159.6 = 0.627 mol. From the reaction, 1 mole of Zn reacts with 1 mole of CuSO4 to form 1 mole of Cu. The limiting reagent is CuSO4. Hence, the moles of Cu formed = 0.627 mol. Mass of Cu formed = 0.627 * 63.55 = 39.86 g ≈ 40 g (Rounding and approximations used). However, as none of the answer choices match the calculated value, the correct answer can't be determined with the given information.