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Problem 8 - Entrance Test

A line in the xy-plane passes through the points (1, 5) and (3, 1). What is the equation of the line?

Correct: A

First, we find the slope of the line: m = (1 - 5) / (3 - 1) = -4 / 2 = -2. Now we use the point-slope form of a line: y - y₁ = m(x - x₁). Using the point (1, 5), we get y - 5 = -2(x - 1). Simplifying, we have y - 5 = -2x + 2, so y = -2x + 7.