If the average (arithmetic mean) of 5 consecutive integers is 12, what is the largest of these integers?
Correct: E
Let the five consecutive integers be n, n + 1, n + 2, n + 3, and n + 4. Their average is (n + (n + 1) + (n + 2) + (n + 3) + (n + 4)) / 5 = (5n + 10) / 5 = n + 2. We are given that the average is 12, so n + 2 = 12. Then n = 10. The largest integer is n + 4 = 10 + 4 = 14.