What is the area of a regular hexagon with side length 4?
Correct: C
A regular hexagon can be divided into six equilateral triangles. The area of an equilateral triangle with side length s is (s^2√3) / 4. In this case, s = 4, so the area of one equilateral triangle is (4^2√3) / 4 = (16√3) / 4 = 4√3. Since there are six equilateral triangles, the area of the hexagon is 6 * 4√3 = 24√3.