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Problem 15 - Entrance Test

What is the equation of a circle with center (-2, 3) and radius 4?

A. (x - 2)^2 + (y + 3)^2 = 16B. (x + 2)^2 + (y - 3)^2 = 16C. (x - 2)^2 + (y + 3)^2 = 4D. (x + 2)^2 + (y - 3)^2 = 4E. x^2 + y^2 = 16

Correct: B

The equation of a circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2. In this case, the center is (-2, 3) and the radius is 4, so the equation is (x - (-2))^2 + (y - 3)^2 = 4^2, which simplifies to (x + 2)^2 + (y - 3)^2 = 16.