A bag contains 5 red balls and 3 blue balls. Two balls are drawn at random without replacement. What is the probability that both balls are red?
Correct: A
The probability of drawing a red ball on the first draw is 5/8. After drawing one red ball, there are 4 red balls and 3 blue balls remaining, for a total of 7 balls. The probability of drawing a red ball on the second draw, given that the first ball was red, is 4/7. Therefore, the probability of drawing two red balls is (5/8) * (4/7) = 20/56 = 5/14.