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Problem 9 - Entrance Test

Convert the polar equation r = 4 / (2 - cos(θ)) to its rectangular form.

Correct: A

We use the standard conversions between polar and rectangular coordinates: x = rcos(θ) y = rsin(θ) r = √(x² + y²) Given the polar equation: r = 4 / (2 - cos(θ)) Multiply both sides by (2 - cos(θ)): 2r - rcos(θ) = 4 Substitute r = √(x² + y²) and rcos(θ) = x: 2√(x² + y²) - x = 4 Isolate the square root term: 2√(x² + y²) = 4 + x Square both sides to eliminate the square root: (2√(x² + y²))² = (4 + x)² 4(x² + y²) = 16 + 8x + x² Distribute and rearrange terms to form a general conic equation: 4x² + 4y² = 16 + 8x + x² 4x² - x² - 8x + 4y² - 16 = 0 3x² - 8x + 4y² - 16 = 0 This is the equation of an ellipse. The final answer is A.