A 5 kg block of ice at 0°C is melted into water and heated to 100°C. What is the total entropy change? (Latent heat of fusion = 344 kJ/kg, specific heat = 4.184 kJ/kg°C)
Correct: D
Entropy change has two parts: melting and heating. ΔS = (mL)/T_fusion + m c ln(T2/T1) = (5×344000)/273 + 5×4184×ln(373/273) ≈ 6289 + 1873 ≈ 8162 J/K. Closest to 8230 J/K.