In a Young's double-slit experiment, the slit separation is 0.1 mm and the distance to the screen is 1 m. If the wavelength of light used is 500 nm, what is the fringe width?
Correct: B
The fringe width is given by β = λD/d, where λ is the wavelength, D is the distance to the screen, and d is the slit separation. Thus, β = (500 * 10⁻⁹ m) * (1 m) / (0.1 * 10⁻³ m) = 5 * 10⁻³ m = 5 mm.