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Problem 15 - Entrance Test

Two resistors of 4 Ω and 6 Ω are connected in parallel. What is the equivalent resistance of the combination?

Correct: A

For resistors in parallel, 1/R_eq = 1/R₁ + 1/R₂. So, 1/R_eq = 1/4 + 1/6 = (3 + 2) / 12 = 5/12. Thus, R_eq = 12/5 = 2.4 Ω.