What is the energy of a photon of light with a wavelength of 600 nm? (h = 6.626 x 10⁻³⁴ Js, c = 3 x 10⁸ m/s)
Correct: A
Energy of a photon E = hc/λ = (6.626 x 10⁻³⁴ * 3 x 10⁸) / (600 x 10⁻⁹) = 3.313 x 10⁻¹⁹ J. Converting to eV: E = (3.313 x 10⁻¹⁹) / (1.6 x 10⁻¹⁹) = 2.07 eV.