Problem 10 - Entrance Test

This is an indeterminate form 0/0. Using L'Hôpital's Rule: lim (x→0) (e^(2x) - 1 - 2x) / x² = lim (x→0) (2e^(2x) - 2) / (2x). This is still an indeterminate form 0/0. Applying L'Hôpital's Rule again: lim (x→0) (4e^(2x)) / 2 = 4e^(0) / 2 = 4/2 = 2.