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Problem 17 - Entrance Test

If x = a cos θ and y = b sin θ, then the value of b²x² + a²y² is:

Correct: A

Given x = a cos θ, we can write cos θ = x/a. Given y = b sin θ, we can write sin θ = y/b. We know the fundamental trigonometric identity: sin² θ + cos² θ = 1. Substitute the expressions for sin θ and cos θ into the identity: (y/b)² + (x/a)² = 1 y²/b² + x²/a² = 1 To combine the terms on the left side, find a common denominator (a²b²): (a²y² + b²x²) / (a²b²) = 1 Multiply both sides by a²b²: a²y² + b²x² = a²b².