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Problem 14 - Entrance Test

If cot θ = 7/8, then the value of (1 + sin θ)(1 - sin θ) / (1 + cos θ)(1 - cos θ) is:

Correct: A

The given expression is (1 + sin θ)(1 - sin θ) / (1 + cos θ)(1 - cos θ). Using the algebraic identity (a + b)(a - b) = a² - b²: Numerator: (1 + sin θ)(1 - sin θ) = 1² - sin² θ = cos² θ. Denominator: (1 + cos θ)(1 - cos θ) = 1² - cos² θ = sin² θ. So, the expression simplifies to cos² θ / sin² θ. We know that cos θ / sin θ = cot θ. Therefore, cos² θ / sin² θ = (cot θ)². Given cot θ = 7/8. So, (cot θ)² = (7/8)² = 49/64.