If sin A = 3/5 and A is an acute angle, then find the value of tan A.
Correct: A
Given sin A = 3/5. In a right-angled triangle, sin A = Perpendicular / Hypotenuse. Let the perpendicular side be 3k and the hypotenuse be 5k for some constant k.
Using the Pythagorean theorem, Base² = Hypotenuse² - Perpendicular²:
Base² = (5k)² - (3k)² = 25k² - 9k² = 16k².
So, Base = √(16k²) = 4k.
Now, tan A = Perpendicular / Base = 3k / 4k = 3/4.