A spring-mass system oscillates horizontally with amplitude A. When it reaches x = A/2, its potential energy is E_p. What is its kinetic energy at x = -A/2?
Correct: A
Potential energy in SHM is E_p = (1/2)kx². At x = ±A/2, potential energy is (1/2)k(A²/4) = E_p. Kinetic energy is total energy (KE + PE). Since energy is conserved, KE at x = ±A/2 is same as E_p.