What is the output of the following Python code?
```python
def my_function(x, y=2):
return x ** y
print(my_function(3))
```
Correct: B
The function `my_function` takes two arguments: `x` and `y`, where `y` has a default value of 2. When the function is called with only one argument (3), it uses the default value of `y`, which is 2. Therefore, the function calculates 3 ** 2 (3 raised to the power of 2), which equals 9.