Daily Olympiad: Chemistry - Electrochemistry [20260611]

Challenge yourself with today's JEE Main practice! This test covers 'Electrochemistry' for Chemistry (JEE Main - 12). Level: Hard | Duration: 45 mins.

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1. For a galvanic cell with Zn | Zn²⁺ (1M) || Cu²⁺ (0.1M) | Cu, calculate the cell potential. Given: E°(Zn²+/Zn) = -0.762 V, E°(Cu²+/Cu) = +0.34 V. (Assume 298 K)

A. 1.07 V B. 1.10 V C. 1.13 V D. 1.16 V

Solution

Correct: A

E°cell = 0.34 - (-0.762) = 1.102 V. Apply Nernst equation: E = E° - (0.0592/2) log([Zn²⁺]/[Cu²⁺]) = 1.102 - (0.0592/2) log(1/0.1) = 1.102 - 0.0296 = 1.07 V.

2. Which statement about the standard hydrogen electrode (SHE) is incorrect?

A. It operates at 1 atm H₂ and 1M H⁺ at 298 K B. It serves as a reference with an assigned potential of 0.00 V C. It uses a platinized platinum electrode D. Its potential doubles when the H₂ gas pressure is 2 atm

Solution

Correct: D

The SHE is defined with fixed conditions (1M H⁺, 1 atm H₂) at 298 K, and its potential is always 0.00 V regardless of stoichiometry. Options B and C are correct. The potential doesn't depend on pressure under standard conditions.

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Daily Olympiad: Chemistry - Electrochemistry [20260611]

1. For a galvanic cell with Zn | Zn²⁺ (1M) || Cu²⁺ (0.1M) | Cu, calculate the cell potential. Given: E°(Zn²+/Zn) = -0.762 V, E°(Cu²+/Cu) = +0.34 V. (Assume 298 K)

2. Which statement about the standard hydrogen electrode (SHE) is incorrect?

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